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Verification Using Simple-Geometry Models

Elastic Static Analysis

This verification uses a cantilever beam meshed as shown in Figure 9.1.1. Seven cases, exA through exG, were analyzed using the loading conditions shown in Figure 9.1.2. Case exG uses the same loading conditions as exA, but with a direct solver.

Verification results for each loading condition are shown in Tables 9.1.1 through 9.1.7.

Example of a cantilever-beam mesh (hexahedral elements) Figure 9.1.1 Example of a Cantilever-Beam Mesh (Hexahedral Elements)

(a) exA and exG: Concentrated load
(b) exD: Gravitational load
(c) exB: Distributed surface load
(d) exE: Centrifugal force
(e) exC: Body load
(f) exF: Thermal load
Item Value
Young's modulus \(E = 4000.0\ \mathrm{kgf/mm^2}\)
Length \(L = 10.0\ \mathrm{mm}\)
Poisson's ratio \(\nu = 0.3\)
Cross-sectional area \(A = 1.0\ \mathrm{mm^2}\)
Mass density \(\rho = 8.0102 \times 10^{-10}\ \mathrm{kgf}\;\mathrm{s}^2/\mathrm{mm}^4\)
Second moment of area \(I = 1.0/12.0\ \mathrm{mm^4}\)
Gravitational acceleration \(g = 9800.0\ \mathrm{mm/s^2}\)
Coefficient of linear thermal expansion \(\alpha = 1.0 \times 10^{-5}\)

Figure 9.1.2 Verification Conditions for the Cantilever-Beam Model

Table 9.1.1 exA: Verification Results for the Concentrated-Load Problem

Case Name Number of Elements Predicted Value: \(\delta_{max}= -1.000\) Remarks
NASTRAN Commercial Software FrontISTR
A231 40 -0.338 -0.371 -0.371 33 nodes / plane-stress problem
A232 40 -0.942 -1.002 -1.002 105 nodes / plane-stress problem
A241 20 -0.720 -0.711 -0.711 33 nodes / plane-stress problem
A242 20 -0.910 -1.002 -1.002 85 nodes / plane-stress problem
A341 240 -0.384 -0.384 -0.386 99 nodes
A342 240 -0.990 -0.990 -0.999 525 nodes
A351 80 -0.353 -0.355 -0.351 99 nodes
A352 80 -0.993 -0.993 -0.992 381 nodes
A361 40 -0.954 -0.985 -0.984 99 nodes
A362 40 -0.994 -0.993 -0.993 220 nodes
A731 40 - - -0.991 33 nodes / direct solver
A741 20 - - -0.996 33 nodes / direct solver

Table 9.1.2 exB: Verification Results for the Distributed-Surface-Load Problem

Case Name Number of Elements Predicted Value: \(\delta_{max}= -3.750\) Remarks
NASTRAN Commercial Software FrontISTR
B231 40 -1.281 -1.403 -1.403 33 nodes / plane-stress problem
B232 40 -3.579 -3.763 -3.763 105 nodes / plane-stress problem
B241 20 -3.198 -2.680 -2.680 33 nodes / plane-stress problem
B242 20 -3.426 -3.765 -3.765 85 nodes / plane-stress problem
B341 240 -1.088 -1.449 -1.454 99 nodes
B342 240 -3.704 -3.704 -3.748 525 nodes
B351 80 -3.547 -1.338 -1.325 99 nodes
B352 80 -0.3717 -3.716 -3.713 381 nodes
B361 40 -3.557 -3.691 -3.688 99 nodes
B362 40 -3.726 -3.717 -3.717 220 nodes
B731 40 - - -3.722 33 nodes / direct solver
B741 20 - - -3.743 33 nodes / direct solver

Table 9.1.3 exC: Verification Results for the Body-Load Problem

Case Name Number of Elements Predicted Value: \(\delta_{max} = -2.944 \times 10^{-5}\) Remarks
NASTRAN Commercial Software FrontISTR
C231 40 - -1.101e-5 -1.101e-5 33 nodes / plane-stress problem
C232 40 - -2.951e-5 -2.951e-5 105 nodes / plane-stress problem
C241 20 - -2.102e-5 -2.102e-5 33 nodes / plane-stress problem
C242 20 - -2.953e-5 -2.953e-5 85 nodes / plane-stress problem
C341 240 - -1.136e-5 -1.140e-5 99 nodes
C342 240 - -2.905e-5 -2.937e-5 525 nodes
C351 80 - -1.050e-5 -1.039e-5 99 nodes
C352 80 - -2.914e-5 -2.911e-5 381 nodes
C361 40 - -2.895e-5 -2.893e-5 99 nodes
C362 40 - -2.915e-5 -2.915e-5 220 nodes
C731 40 - - -2.922e-5 33 nodes / direct solver
C741 20 - - -2.938e-5 33 nodes / direct solver

Table 9.1.4 exD: Verification Results for the Gravitational-Load Problem

Case Name Number of Elements Predicted Value: \(\delta_{max} = -2.944 \times 10^{-5}\) Remarks
NASTRAN Commercial Software FrontISTR
D231 40 -1.101e-5 -1.101e-5 -1.101e-5 33 nodes / plane-stress problem
D232 40 -2.805e-5 -2.951e-5 -2.951e-5 105 nodes / plane-stress problem
D241 20 -2.508e-5 -2.102e-5 -2.102e-5 33 nodes / plane-stress problem
D242 20 -2.684e-5 -2.953e-5 -2.953e-5 85 nodes / plane-stress problem
D341 240 -1.172e-5 -1.136e-5 -1.140e-5 99 nodes
D342 240 -2.906e-5 -2.905e-5 -2.937e-5 525 nodes
D351 80 -1.046e-5 -1.050e-5 -1.039e-5 99 nodes
D352 80 -2.917e-5 -2.914e-5 -2.911e-5 381 nodes
D361 40 -2.800e-5 -2.895e-5 -2.893e-5 99 nodes
D362 40 -2.919e-5 -2.915e-5 -2.915e-5 220 nodes
D731 40 - - -2.922e-5 33 nodes / direct solver
D741 20 - - -2.938e-5 33 nodes / direct solver

Table 9.1.5 exE: Verification Results for the Centrifugal-Force Problem

Case Name Number of Elements Predicted Value: \(\delta_{max} = 2.635 \times 10^{-3}\) Remarks
NASTRAN Commercial Software FrontISTR
E231 40 2.410e-3 2.616e-3 2.650e-3 33 nodes / plane-stress problem
E232 40 2.447e-3 2.627e-3 2.628e-3 105 nodes / plane-stress problem
E241 20 2.386e-3 2.622e-3 2.624e-3 33 nodes / plane-stress problem
E242 20 2.387e-3 2.627e-3 2.629e-3 85 nodes / plane-stress problem
E341 240 2.708e-3 2.579e-3 2.625e-3 99 nodes
E342 240 2.639e-3 2.614e-3 2.638e-3 525 nodes
E351 80 2.642e-3 2.598e-3 2.625e-3 99 nodes
E352 80 2.664e-3 2.617e-3 2.616e-3 381 nodes
E361 40 2.611e-3 2.603e-3 2.603e-3 99 nodes
E362 40 2.623e-3 2.616e-3 2.616e-3 220 nodes
E731 40 - - 2.619e-3 33 nodes / direct solver
E741 20 - - 2.622e-3 33 nodes / direct solver

Table 9.1.6 exF: Verification Results for the Thermal-Stress Load Problem

Case Name Number of Elements Predicted Value: \(\delta_{max} = 1.000 \times 10^{-2}\) Remarks
NASTRAN Commercial Software FrontISTR
F231 40 - 1.016e-2 1.007e-2 33 nodes / plane-stress problem
F232 40 - 1.007e-2 1.007e-2 105 nodes / plane-stress problem
F241 20 - 1.010e-2 1.010e-2 33 nodes / plane-stress problem
F242 20 - 1.006e-2 1.006e-2 85 nodes / plane-stress problem
F341 240 - 1.047e-2 1.083e-2 99 nodes
F342 240 - 1.018e-2 1.022e-2 525 nodes
F351 80 - 1.031e-2 1.062e-2 99 nodes
F352 80 - 1.015e-2 1.017e-2 381 nodes
F361 40 - 1.026e-2 1.026e-2 99 nodes
F362 40 - 1.016e-2 1.016e-2 220 nodes

Table 9.1.7 exG: Direct-Solver Verification Results (Concentrated-Load Problem)

Case Name Number of Elements Predicted Value: δmax= -1.000 Remarks
NASTRAN Commercial Software FrontISTR
G231 40 -0.338 -0.371 -0.371 33 nodes / plane-stress problem
G232 40 -0.942 -1.002 -1.002 105 nodes / plane-stress problem
G241 20 -0.720 -0.711 -0.711 33 nodes / plane-stress problem
G242 20 -0.910 -1.002 -1.002 85 nodes / plane-stress problem
G341 240 -0.384 -0.384 -0.386 99 nodes
G342 240 -0.990 -0.990 -0.999 525 nodes
G351 80 -0.353 -0.355 -0.351 99 nodes
G352 80 -0.993 -0.993 -0.992 381 nodes
G361 40 -0.954 -0.985 -0.984 99 nodes
G362 40 -0.994 -0.993 -0.993 220 nodes
G731 40 - - -0.991 33 nodes / direct solver
G741 20 - - -0.996 33 nodes / direct solver

Nonlinear Static Analysis

(2-1) exnl1: Geometric Nonlinear Analysis

The verification model for case exI is identical to the models for cases exA through exG. Figure 9.1.3 shows a schematic of the verification model. Geometric nonlinear analysis is performed on this model. The verification results are shown in Table 9.1.8.

The nonlinear calculation uses a reference load of \(P = 1.0\ \mathrm{kgf}\), with an increment of \(0.1P\) over 10 load steps.

Verification model Figure 9.1.3 Verification Model

Table 9.1.8 exI: Verification Results (Maximum-Deflection History)

Case Name 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Linear Solution
I231 - - - - - - - - - - -
I232 - - - - - - - - - - -
I241 - - - - - - - - - - -
I242 - - - - - - - - - - -
I341 0.039 0.077 0.116 0.154 0.193 0.232 0.270 0.309 0.348 0.386 0.386
I342 0.099 0.200 0.300 0.400 0.499 0.599 0.698 0.797 0.896 0.995 0.999
I351 0.035 0.070 0.105 0.141 0.176 0.211 0.246 0.281 0.316 0.351 0.351
I352 0.099 0.198 0.298 0.397 0.496 0.595 0.693 0.792 0.890 0.987 0.992
I361 0.070 0.139 0.209 0.278 0.348 0.417 0.487 0.556 0.625 0.694 0.984
I362 0.099 0.197 0.298 0.397 0.496 0.595 0.694 0.793 0.891 0.988 0.993

(2-2) exnl2: Elastoplastic Deformation Analysis

This verification problem is based on NAFEMS Test NL1 from the National Agency for Finite Element Methods and Standards (U.K.), and evaluates elastoplastic deformation with geometric nonlinearity and multiple hardening laws. Figure 9.1.4 shows the analysis model.

Elastoplastic deformation analysis model

Figure 9.1.4 Elastoplastic Deformation Analysis Model

(1) Verification Conditions

Item Value
Material Mises elastoplastic material
Young's modulus \(E = 250\ \mathrm{GPa}\)
Poisson's ratio \(\nu=0.25\)
Initial yield stress \(5\ \mathrm{MPa}\)
Initial yield strain \(0.25\times10^{-4}\)
Isotropic hardening coefficient \(H_i = 0\) or \(62.5\ \mathrm{GPa}\)

(2) Boundary Conditions

Item Boundary Condition Value
Step 1 Prescribed displacement at nodes 2 and 3 \(u_x = 0.2500031251 * 10^{-4}\)
Step 2 Prescribed displacement at nodes 2 and 3 \(u_x = 0.25000937518 * 10^{-4}\)
Step 3 Prescribed displacement at nodes 3 and 4 \(u_y = 0.2500031251 * 10^{-4}\)
Step 4 Prescribed displacement at nodes 3 and 4 \(u_y = 0.25000937518 * 10^{-4}\)
Step 5 Prescribed displacement at nodes 2 and 3 \(u_x = -0.25000937518 * 10^{-4}\)
Step 6 Prescribed displacement at nodes 2 and 3 \(u_x = -0.2500031251 * 10^{-4}\)
Step 7 Prescribed displacement at nodes 3 and 4 \(u_y = -0.25000937518 * 10^{-4}\)
Step 8 Prescribed displacement at nodes 3 and 4 \(u_y = -0.2500031251 * 10^{-4}\)

All nodes not listed here are fully constrained. The theoretical solution for this problem is as follows.

Strain (\(\times10^{-4}\))
[\(\varepsilon_x\), \(\varepsilon_y\), \(\varepsilon_z\)]
Equivalent stress (MPa)
[\(H_i=0\ H_k=0\); \(H_i=62.5\ H_k=0\)]
0.25, 0, 0 5.0; 5.0
0.50, 0, 0 5.0; 5.862
0.50, 0.25, 0 5.0; 5.482
0.50, 0.50, 0 5.0; 6.362
0.25, 0.50, 0 5.0; 6.640
0, 0.50, 0 5.0; 7.322
0, 0.25, 0 3.917; 4.230
0, 0, 0 5.0; 5.673

The calculation results are as follows.

Strain (\(\times10^{-4}\))
[\(\varepsilon_x\), \(\varepsilon_y\), \(\varepsilon_z\)]
Equivalent stress (MPa)
[\(H_i=0\ H_k=0\); \(H_i=62.5\ H_k=0\)]
\(\varepsilon_{x}\) \(\varepsilon_{y}\)
0.25, 0, 0 5.0 (0.0%); 5.0 (0.0%)
0.50, 0, 0 5.0 (0.0%); 5.862 (0.0%)
0.50, 0.25, 0 5.0 (0.0%); 5.482 (0.0%)
0.50, 0.50, 0 5.0 (0.0%); 6.362 (-0.05%)
0.25, 0.50, 0 5.0 (0.0%); 6.640 (-0.21%)
0, 0.50, 0 5.0 (0.0%); 7.322 (-0.34%)
0, 0.25, 0 3.824 (-2.4%); 4.230 (-2.70%)
0, 0, 0 5.0 (0.0%); 5.673 (5.673 (-2.50%)

Contact Analysis (1)

This verification problem is based on contact patch test CGS-4 from the National Agency for Finite Element Methods and Standards (U.K.), and tests the finite-sliding contact capability with friction. Figure 9.1.5 shows the analysis model.

Contact analysis model

Figure 9.1.5 Contact Analysis Model

The equilibrium condition for this problem is as follows.

\[ F \cos \alpha - G \sin \alpha = \pm f_{c} \]

In the sticking-friction stage, the friction force is

\[ f_{c} = E_t \Delta u \]

whereas in the sliding-friction stage, it is

\[ f_{c} = \mu(G \cos \alpha + F \sin \alpha) \]

This gives the relation above.

The calculated results are compared with the analytical solution below.

\(\mu\) \(F/G\) Analytical Solution \(F/G\) Calculated Result
0.0 0.1 0.1
0.1 0.202 0.202
0.2 0.306 0.306
0.3 0.412 0.412

Contact Analysis (2): Hertz Contact Problem

This verification analyzes the Hertz contact problem between an infinitely long cylinder and an infinite plane. The cylinder radius is \(R = 8\ \mathrm{mm}\), and the Young's modulus \(E\) and Poisson's ratio \(\mu\) of the deformable body are \(1100\ \mathrm{MPa}\) and \(0.0\), respectively. The contact area is assumed to be sufficiently small relative to the cylinder radius. Accounting for symmetry, the analysis uses a quarter-cylinder model.

Hertz contact problem analysis model Figure 9.1.6 Analysis Model for the Hertz Contact Problem

(1) Verification Results for the Contact Radius

The theoretical equation for calculating the contact radius is as follows.

\[ a = \sqrt{\frac{4FR}{\pi E^{*}}} \]

where

\[ E^{*} = E/2(1 - \mu^{2}) \]

This gives the expression above. For the present calculation, when the pressure is \(F=100\), the contact radius is \(a=1.36\).

Figure 9.1.7 shows the equivalent nodal forces at the contact points. The contact radius is obtained by extrapolating this nodal-force distribution.

Equivalent nodal-force distribution at the contact points

Figure 9.1.7 Equivalent Nodal-Force Distribution at the Contact Points

(2) Verification Results for the Maximum Shear Stress

In the theoretical solution, at the contact position

\[ z = 0.78a \]

the maximum shear stress is

\[ \tau_{\max} = 0.30\sqrt{\frac{\text{FE}^{*}}{\pi R}} \]

This is the theoretical maximum shear stress. For the present calculation conditions,

\[ \tau_{\max} = 14.2 \]

This is the theoretical value under the present conditions. The calculation, however, gives

\[ \tau_{\max} = 15.6 \]

This is the calculated result.

Shear-stress distribution (maximum value = 15.6 Figure 9.1.8 Shear-Stress Distribution (Maximum Value = 15.6)

(3) Modal Analysis

The verification models for cases exJ and exK are identical to those for cases exA through exG. Figure 9.1.9 shows a schematic of the verification model. Modal analysis is performed on this model. The first through third natural frequencies are calculated. Case exJ uses an iterative solver, whereas case exK uses a direct solver. The verification results are shown in Tables 9.1.9 through 9.1.12.

Verification model Figure 9.1.9 Verification Model

The natural frequencies of the cantilever beam are given by the following equations.

First natural frequency

\[ n_1 = \frac{1.875^2}{2 \pi l^2} \sqrt{ \frac{gEI}{\omega} } \]

Second natural frequency

\[ n_2 = \frac{4.694^2}{2 \pi l^2} \sqrt{ \frac{gEI}{\omega} } \]

Third natural frequency

\[ n_3 = \frac{7.855^2}{2 \pi l^2} \sqrt{ \frac{gEI}{\omega} } \]

The properties of the verification model are

Item Value
\(I\) \(1.0/12.0\ \mathrm{mm}^4\)
\(E\) \(4000.0\ \mathrm{kgf/mm^2}\)
\(l\) \(10.0\ \mathrm{mm}\)
\(\omega\) \(7.85 \times 10^{-6}\ \mathrm{kgf/mm^3}\)
\(g\) \(9800.0\ \mathrm{mm/s^2}\)

Thus, the first three natural frequencies are as follows.

Mode Number Value
\(n_1\) 3.609e3
\(n_2\) 2.262e4
\(n_3\) 6.335e4

Table 9.1.9 exJ: Iterative-Solver Verification Results (First Natural Frequency)

Case Name Number of Elements Predicted Value: n1=3.609e3 Remarks
NASTRAN FrontISTR
J231 40 5.861e3 5.861e3 33 nodes / plane-stress problem
J232 40 3.596e3 3.593e3 105 nodes / plane-stress problem
J241 20 3.586e3 4.245e3 33 nodes / plane-stress problem
J242 20 3.590e3 3.587e3 85 nodes / plane-stress problem
J341 240 5.442e3 5.429e3 99 nodes
J342 240 3.621e3 3.595e3 525 nodes
J351 80 3.695e3 4.298e3 99 nodes
J352 80 3.610e3 3.609e3 381 nodes
J361 40 3.679e3 3.619e3 99 nodes
J362 40 3.611e3 3.606e3 220 nodes

Table 9.1.10 exJ: Iterative-Solver Verification Results (Second Natural Frequency)

Case Name Number of Elements Predicted Value: n2=2.262e4 Remarks
NASTRAN FrontISTR
J231 40 3.350e4 3.351e4 33 nodes / plane-stress problem
J232 40 2.163e4 2.156e4 105 nodes / plane-stress problem
J241 20 2.149e4 2.516e4 33 nodes / plane-stress problem
J242 20 2.149e4 2.143e4 85 nodes / plane-stress problem
J341 240 3.145e4 3.138e4 99 nodes
J342 240 2.171e4 2.155e4 525 nodes
J351 80 2.208e4 2.546e4 99 nodes
J352 80 2.156e4 2.149e4 381 nodes
J361 40 2.202e4 2.168e4 99 nodes
J362 40 2.154e4 2.144e4 220 nodes

Note: In three-dimensional models, the first two modes are degenerate; therefore, the third computed natural frequency is reported as the second natural frequency in the table.

Table 9.1.11 exK: Direct-Solver Verification Results (First Natural Frequency)

Case Name Number of Elements Predicted Value: n1=3.609e3 Remarks
NASTRAN FrontISTR
J231 40 5.861e3 5.861e3 33 nodes / plane-stress problem
J232 40 3.596e3 3.593e3 105 nodes / plane-stress problem
J241 20 3.586e3 4.245e3 33 nodes / plane-stress problem
J242 20 3.590e3 3.587e3 85 nodes / plane-stress problem
J341 240 5.442e3 5.429e3 99 nodes
J342 240 3.621e3 3.595e3 525 nodes
J351 80 3.695e3 4.298e3 99 nodes
J352 80 3.610e3 3.609e3 381 nodes
J361 40 3.679e3 3.619e3 99 nodes
J362 40 3.611e3 3.606e3 220 nodes
J731 40 - 3.606e3 220 nodes
J741 20 - 3.594e3 220 nodes

Table 9.1.12 exK: Direct-Solver Verification Results (Second Natural Frequency)

Case Name Number of Elements Predicted Value: n2=2.262e4 Remarks
NASTRAN FrontISTR
J231 40 3.350e4 3.351e4 33 nodes / plane-stress problem
J232 40 2.163e4 2.156e4 105 nodes / plane-stress problem
J241 20 2.149e4 2.516e4 33 nodes / plane-stress problem
J242 20 2.149e4 2.143e4 85 nodes / plane-stress problem
J341 240 3.145e4 3.138e4 99 nodes
J342 240 2.171e4 2.155e4 525 nodes
J351 80 2.208e4 2.546e4 99 nodes
J352 80 2.156e4 2.149e4 381 nodes
J361 40 2.202e4 2.168e4 99 nodes
J362 40 2.154e4 2.144e4 220 nodes
J731 40 - 2.156e4 220 nodes
J741 20 - 2.153e4 220 nodes

Note: In three-dimensional models, the first two modes are degenerate; therefore, the third computed natural frequency is reported as the second natural frequency in the table.

(4) Heat Conduction Analysis

The common conditions for steady-state heat conduction analysis are shown in Figure 9.1.10. The individual conditions for verification cases exM through exT are shown in Figure 9.1.11. The same mesh as for exA is used.

Tables 9.1.13 through 9.1.20 show the temperature-distribution results for each case.

Heat conduction analysis

Distance between A and B \(L = 10.0\ \mathrm{m}\)
Cross-sectional area \(A = 1.0\ \mathrm{m^2}\)

Temperature Dependence of Thermal Conductivity

Thermal Conductivity \(\lambda\) (W/(m·K)) Temperature (°C)
50.0 0.0
35.0 500.0
20.0 1000.0

Figure 9.1.10 Verification Conditions for Steady-State Heat Conduction Analysis

exM: Linear material
exN: Prescribed-temperature problem
exO: Concentrated heat-flux problem
exP: Distributed heat-flux problem
exQ: Convective heat-transfer problem
exR: Radiative heat-transfer problem
exS: Volumetric heat-generation problem
exT: Internal-gap problem

Figure 9.1.11 Analysis Conditions for Each Verification Case

Table 9.1.13 exM: Verification Results for Steady-State Calculation with a Linear Material

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
M361A 361 40/33 0.0 100.0 200.0 300.0 400.0 500.0
M361B 361 40/105 0.0 100.0 200.0 300.0 400.0 500.0
M361C 361 20/33 0.0 100.0 200.0 300.0 400.0 500.0
M361D 361 20/85 0.0 100.0 200.0 300.0 400.0 500.0
M361E 361 240/99 0.0 100.0 200.0 300.0 400.0 500.0
M361F 361 24/525 0.0 100.0 200.0 300.0 400.0 500.0
M361G 361 80/99 0.0 100.0 200.0 300.0 400.0 500.0

Table 9.1.14 exN: Verification Results for the Prescribed-Temperature Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 87.3 179.7 278.2 384.3 500.0
N231 231 40/33 0.0 87.2 179.5 278.0 384.1 500.0
N232 232 40/105 0.0 86.0 178.3 276.8 382.9 500.0
N241 241 20/33 0.0 87.3 179.7 278.2 384.3 500.0
N242 242 20/85 0.0 87.3 179.7 278.2 384.3 500.0
N341 341 240/99 0.0 87.3 179.7 278.2 384.3 500.0
N342 342 24/525 0.0 87.9 179.9 278.0 383.6 500.0
N351 351 80/99 0.0 87.3 179.7 278.2 384.3 500.0
N352 352 80/381 0.0 87.3 179.7 278.2 384.3 500.0
N361 361 40/99 0.0 87.3 179.7 278.2 384.3 500.0
N362 362 40/330 0.0 87.3 179.7 278.2 384.3 500.0
N731 731 40/33 0.0 87.3 179.7 278.2 384.3 500.0
N741 741 20/33 0.0 87.3 179.7 278.2 384.3 500.0

Table 9.1.15 exO: Verification Results for the Concentrated-Heat-Flux Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 103.2 213.7 333.3 464.8 612.6
O231 231 40/33 0.0 103.2 213.7 333.3 464.8 612.6
O232 232 40/105 0.0 103.2 213.7 333.3 464.8 612.6
O241 241 20/33 0.0 103.2 213.7 333.3 464.8 612.6
O242 242 20/85 0.0 103.2 213.7 333.4 465.2 618.0
O341 341 240/99 - - - - - -
O342 342 24/525 0.0 104.4 214.9 334.7 466.3 614.6
O351 351 80/99 - - - - - -
O352 352 80/381 0.0 103.2 213.7 333.3 465.0 624.2
O361 361 40/99 0.0 103.2 213.7 333.3 464.8 612.6
O362 362 40/330 0.0 103.2 213.7 333.4 465.5 623.5
O731 731 40/33 0.0 103.2 213.7 333.3 464.8 612.5
O741 741 20/33 0.0 103.2 213.7 333.3 464.8 612.6

Table 9.1.16 exP: Verification Results for the Distributed-Heat-Flux Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 103.2 213.7 333.3 464.8 612.6
P231 231 40/33 0.0 103.2 213.7 333.3 464.8 612.6
P232 232 40/105 0.0 103.2 213.7 333.3 464.8 612.6
P241 241 20/33 0.0 103.2 213.7 333.3 464.8 612.6
P242 242 20/85 0.0 103.2 213.7 333.3 464.8 612.6
P341 341 240/99 - - - - - -
P342 342 24/525 0.0 103.2 213.7 333.3 464.8 612.6
P351 351 80/99 - - - - - -
P352 352 80/381 0.0 103.2 213.7 333.3 464.8 612.6
P361 361 40/99 0.0 103.2 213.7 333.3 464.8 612.6
P362 362 40/330 0.0 103.2 213.7 333.4 465.5 612.6
P731 731 40/33 0.0 103.2 213.7 333.3 464.8 612.5
P741 741 20/33 0.0 103.2 213.7 333.3 464.8 612.6

Table 9.1.17 exQ: Verification Results for the Convective-Heat-Transfer Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 89.2 183.8 284.8 393.9 513.2
Q231 231 40/33 0.0 89.2 183.8 284.8 393.9 513.2
Q232 232 40/105 0.0 89.2 183.8 284.8 393.9 513.2
Q241 241 20/33 0.0 89.2 183.8 284.8 393.9 513.2
Q242 242 20/85 0.0 89.2 183.8 284.8 393.9 513.2
Q341 341 240/99 - - - - - -
Q342 342 24/525 0.0 89.2 183.8 284.8 393.9 513.2
Q351 351 80/99 - - - - - -
Q352 352 80/381 0.0 89.2 183.8 284.8 393.9 513.2
Q361 361 40/99 0.0 89.2 183.8 284.8 393.9 513.2
Q362 362 40/330 0.0 89.2 183.8 284.8 393.9 513.2
Q731 731 40/33 0.0 89.2 183.8 284.8 393.9 513.2
Q741 741 20/33 0.0 89.2 183.8 284.8 393.9 513.2

Table 9.1.18 exR: Verification Results for the Radiative-Heat-Transfer Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 89.5 184.4 285.8 395.3 515.2
R231 231 40/33 0.0 89.5 184.4 285.8 395.3 515.2
R232 232 40/105 0.0 89.5 184.4 285.8 395.3 515.2
R241 241 20/33 0.0 89.5 184.4 285.8 395.3 515.2
R242 242 20/85 0.0 89.5 184.4 285.8 395.3 515.2
R341 341 240/99 - - - - - -
R342 342 24/525 0.0 89.5 184.4 285.8 395.3 515.2
R351 351 80/99 - - - - - -
R352 352 80/381 0.0 89.5 184.4 285.8 395.3 515.2
R361 361 40/99 0.0 89.5 184.4 285.8 395.3 515.2
R362 362 40/330 0.0 89.5 184.4 285.8 395.3 515.2
R731 731 40/33 0.0 89.5 184.4 285.8 395.3 515.2
R741 741 20/33 0.0 89.5 184.4 285.8 395.3 515.2

Table 9.1.19 exS: Verification Results for the Volumetric-Heat-Generation Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 103.2 213.7 333.3 464.8 612.6
S231 231 40/33 0.0 103.2 213.7 333.3 464.8 612.6
S232 232 40/105 0.0 103.2 213.7 333.3 464.8 612.6
S241 241 20/33 0.0 103.2 213.7 333.3 464.8 612.6
S242 242 20/85 0.0 103.2 213.7 333.3 464.8 612.6
S341 341 240/99 - - - - - -
S342 342 24/525 0.0 103.2 213.7 333.3 464.8 612.6
S351 351 80/99 - - - - - -
S352 352 80/381 0.0 103.2 213.7 333.3 464.8 612.6
S361 361 40/99 0.0 103.2 213.7 333.3 464.8 612.6
S362 362 40/330 0.0 103.2 213.7 333.3 464.8 612.6
S731 731 40/33 0.0 103.2 213.7 333.3 464.8 612.6
S741 741 20/33 0.0 103.2 213.7 333.3 464.8 612.6

Table 9.1.20 exT: Verification Results for the Internal-Gap Problem

Case Name Element Type Elements/Nodes Distance from End A (m)
End A 2.0 4.0 6.0 8,0 End B
Commercial Software 361 40/99 0.0 88.6 182.4 282.6 387.7 500.0
S231 231 40/33 0.0 88.6 182.4 282.6 387.7 500.0
S232 232 40/105 0.0 88.6 182.4 282.6 387.7 500.0
S241 241 20/33 0.0 88.6 182.4 282.6 387.7 500.0
S242 242 20/85 0.0 88.6 182.4 282.6 387.7 500.0
S341 341 240/99 - - - - - -
S342 342 24/525 0.0 88.6 182.4 282.6 387.7 500.0
S351 351 80/99 - - - - - -
S352 352 80/381 0.0 88.6 182.4 282.6 387.7 500.0
S361 361 40/99 0.0 88.6 182.4 282.6 387.7 500.0
S362 362 40/330 0.0 88.6 182.4 282.6 387.7 500.0
S731 731 40/33 0.0 88.6 182.4 282.6 387.7 500.0
S741 741 20/33 0.0 88.6 182.4 282.6 387.7 500.0

Linear Dynamic Analysis

In exW, linear dynamic analysis is performed on the same cantilever beam as in Section (1). Figure 9.1.12 shows the verification conditions. The effect of the time increment is verified using the same mesh. Both implicit and explicit methods are used, with element types 361 and 342. The verification results are shown in Table 9.1.22 and Figures 9.1.13 through 9.1.15.

Analysis model Analysis Model

Time history of external force F Time History of External Force F

The theoretical solution for displacement at the excitation point is as follows:

\[ F(t)=F_0 I(t) \]

where

\[ \(F_0:\ \text{Constant vector}\) \]
\[ I(t)= \begin{cases} 0, t < 0 \\\ 1, 0 \leq t \end{cases} \]
\[ u(t) = \frac{F_0 l^3}{EI} \sum^{\infty}_{i=1} \frac{1-\cos{\omega_i t}}{{\lambda_i}^4} \left\lbrace \cosh{\lambda_i}-\cos{\lambda_i}-\frac{\cosh{\lambda_i} + \cos{\lambda_i}}{\sin{\lambda_i}+\sin{\lambda_i}} (\sinh{\lambda_i} - \sin{\lambda_i}) \right\rbrace^2 \]

Figure 9.1.12 Verification Conditions for Linear Dynamic Analysis

Verification Conditions:

Length \(L\) \(10.0\ \mathrm{mm}\)
Cross-sectional width \(a\) \(1.0\ \mathrm{mm}\)
Cross-sectional height \(b\) \(1.0\ \mathrm{mm}\)
Young's modulus \(E\) \(4000.0\ \mathrm{kgf/mm^2}\)
Poisson's ratio \(\nu\) \(0.3\)
Density \(\rho\) \(1.0 \times 10^{-9}\ \mathrm{kgf}\;\mathrm{s}^2/\mathrm{mm}^4\)
Gravitational acceleration \(g\) \(9800.0\ \mathrm{mm/s^2}\)
External force \(F_0\) \(1.0\ \mathrm{kgf}\)
Element First-order hexahedral element
Second-order tetrahedral element
Solution Method Implicit method
Newmark-\(\beta\) method parameter \(\gamma\) 1/2
Newmark-\(\beta\) method parameter \(\beta\) 1/4
Explicit method
Damping None

Table 9.1.21 Verification Conditions for Linear Dynamic Analysis (Continued)

Case Name Element Type Number of Nodes Number of Elements Method Time Increment \(\Delta t\) (s)
W361_c0_im_m2_t1 361 99 40 Implicit method 1.0E-06
W361_c0_im_m2_t2 361 99 40 Implicit method 1.0E-05
W361_c0_im_m2_t3 361 99 40 Implicit method 1.0E-04
W361_c0_ex_m2_t1 361 99 40 Implicit method 1.0E-08
W361_c0_ex_m2_t2 361 99 40 Implicit method 1.0E-07
W361_c0_ex_m2_t3 361 99 40 Implicit method 1.0E-06
W342_c0_im_m2_t1 342 525 240 Explicit method 1.0E-06
W342_c0_im_m2_t2 342 525 240 Explicit method 1.0E-05
W342_c0_im_m2_t3 342 525 240 Explicit method 1.0E-04
W342_c0_ex_m2_t1 342 525 240 Explicit method 1.0E-08
W342_c0_ex_m2_t2 342 525 240 Explicit method 5.0E-08
W342_c0_ex_m2_t3 342 525 240 Explicit method 1.0E-07

Table 9.1.22 exW: Verification Results for Linear Dynamic Analysis of a Cantilever Beam

Case Name Element Type Number of Nodes Number of Elements Method z-Direction Displacement at Time \(t = 0.002\ \mathrm{s}\) (mm)
W361_c0_im_m2_t1 361 99 40 Implicit method 1.9753 1.9302
W361_c0_im_m2_t2 361 99 40 Implicit method 1.9753 1.8686
W361_c0_im_m2_t3 361 99 40 Implicit method 1.9753 0.3794
W361_c0_ex_m2_t1 361 99 40 Implicit method 1.9753 1.9302
W361_c0_ex_m2_t2 361 99 40 Implicit method 1.9753 1.9247
W361_c0_ex_m2_t3 361 99 40 Implicit method 1.9753 Diverged
W342_c0_im_m2_t1 342 525 240 Explicit method 1.9753 1.9431
W342_c0_im_m2_t2 342 525 240 Explicit method 1.9753 1.8719
W342_c0_im_m2_t3 342 525 240 Explicit method 1.9753 0.3873
W342_c0_ex_m2_t1 342 525 240 Explicit method 1.9753 1.9359
W342_c0_ex_m2_t2 342 525 240 Explicit method 1.9753 1.9358
W342_c0_ex_m2_t3 342 525 240 Explicit method 1.9753 Diverged

Deformed shape and equivalent stress distribution of the cantilever beam Figure 9.1.13 Deformed Shape and Equivalent Stress Distribution of the Cantilever Beam

(a) Element Type 361: Implicit Method (a) Element Type 361: Implicit Method

(b) Element Type 361: Explicit Method (b) Element Type 361: Explicit Method

Figure 9.1.14 Time History of Excitation-Point Displacement \(u_z\)

(a) Element Type 342: Implicit Method (a) Element Type 342: Implicit Method

(b) Element Type 342: Explicit Method (b) Element Type 342: Explicit Method

Figure 9.1.15 Time History of Excitation-Point Displacement \(u_z\)

Frequency Response Analysis

This verification performs frequency response analysis of a cantilever beam and compares the results with those from general-purpose commercial software. The analysis model and verification conditions are shown below.

Analysis Conditions:

Young's modulus \(E\) \(210000\ \mathrm{N/mm^2}\)
Poisson's ratio \(\nu\) \(0.3\)
Density \(\rho\) \(7.89 \times 10^{-9}\ \mathrm{t/mm^3}\)
Gravitational acceleration \(g\) \(9800.0\ \mathrm{mm/s^2}\)
Load \(F_0\) \(1.0\ \mathrm{N}\)
Rayleigh Damping Parameter \(R_m\) \(0.0\)
Rayleigh Damping Parameter \(R_k\) \(7.2E-07\)

Figure 9.1.16 Analysis Model (First-Order Tetrahedral Elements: 126 Elements, 55 Nodes)

The first five natural frequencies obtained by modal analysis, together with the frequency response at the excitation point, are shown below.

Mode FrontISTR Commercial Software
1 14952 14952
2 15002 15003
3 84604 84539
4 84771 84697
5 127054 126852

Frequency dependence of displacement magnitude at the excitation point Figure 9.1.17 Frequency Dependence of Displacement Magnitude at the Excitation Point